Given three points in the plane, how does one construct three distinct circles which touch in pairs at the three points?
Solution
Take the circumcircle C of the three points. Take the triangle formed by the tangents to the circle at the three points. Its vertices are the required three centers.
For PB = PC, QA = QC, RA = RB.
© John Scholes
jscholes@kalva.demon.co.uk
1 Nov 2003
Last corrected/updated 1 Nov 03