16th Eötvös 1909

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Problem 1

Prove that (n + 1)3 ≠ n3 + (n - 1)3 for any positive integer n.

 

Solution

If we have equality, then n3 = 6n2 + 2. But if n ≤ 6, then n3 ≤ 6n2 < 6n2 + 2. If n ≥ 7, then n3 ≥ 7n2 > 6n2 + 2. Contradiction.

 


 

16th Eötvös 1909

© John Scholes
jscholes@kalva.demon.co.uk
29 Oct 2003
Last corrected/updated 29 Oct 03