ABC is a right-angled triangle. Show that sin A sin B sin(A - B) + sin B sin C sin(B - C) + sin C sin A sin(C - A) + sin(A - B) sin(B - C) sin(C - A) = 0.
Solution
We have 1st term = sin B cos B, 2nd term = -sin B cos B cos 2B, 3rd term = -sin B cos B, 4th term = sin B cos B cos 2B.
© John Scholes
jscholes@kalva.demon.co.uk
29 Oct 2003
Last corrected/updated 29 Oct 03