A triangle ABC has sides BC = a, CA = b, AB = c. Given (1) the radius R of the circumcircle, (2) a, (3) t = b/c, determine b, c and the angles A, B, C.
Solution
As usual we have sin A = a/(2R).
We have tan B = (b sin A)/(c - b cos A) = (t sin A)/(1 - t cos A). Then C = 180o - A - B. Then a/sin A = b/sin B gives b, and c = t/b.
© John Scholes
jscholes@kalva.demon.co.uk
11 Oct 2003
Last corrected/updated 11 Oct 03